(4) 令 √(x-1) = u, 则 x = u^2+1, dx = 2udu原式 = ∫ <0, 1>2(u^2+1)du = [(2/3)u^3 + 2u]<0, 1> = 8/3. 该广义积分收敛。(6) ∫ <0, 2>dx/√(2x-x^2) = ∫ <0, 2>d(x-1)/√[1-(x-1)^2]= [arcsin(x-1)]<0, 2> = π/2 - (-π/2) = π. 该广义积分收敛。
