化简求值:2xy^2-[3xy^2-2(x^2y-(1⼀2)xy^2)]-2x^2y其中x=-2⼀3,y=-1⼀2

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2025-05-11 03:10:11
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回答1:

2xy^2-[3xy^2-2(x^2y-(1/2)xy^2)]-2x^2y
=2xy²-[4xy²-2x²y]-2x²y
=2xy²﹣4xy²﹢2x²y﹣2x²y
=﹣2xy²
=﹣2×﹙﹣2/3﹚﹙﹣1/2﹚
=﹣2/3