设 1+x = u^10,1-x = v^10,原式 = (u^5 - v^5) / (u^2-v^2) = (u^4+u^3v+u^2v^2+uv^3+v^4) / (u+v),然后代入极限 = (1+1+1+1+1)/(1+1) = 5/2 。
参考