高数,级数求和化简。怎么化简最后这一步。

2025-05-10 11:05:47
推荐回答(2个)
回答1:

回答2:

∑(n=2->∞) x^(n+1)/(n+1)
=∑(n=3->∞) x^n/n
=∑(n=1->∞) x^n/n-(x^2/2)-(x^1/1)
=ln(1-x)-(x^2/2)-x