设随机变量X的分布函数为F(X)=1-a대⼀x대,X≥a。其中a>0,求E(X)

2025-05-10 12:11:31
推荐回答(1个)
回答1:

F(x) = 1 - a^3/x^3 ; x≥a
=0 ; elsewhere

f(x) = F'(x)
=3a^3/x^4 ; x≥a
=0 ; elsewhere

E(X)
= ∫(a->∞) xf(x) dx
= ∫(a->∞) 3a^3/x^3 dx
=-(3/2)a^3.[1/x^2]|(a->∞)
=(3/2)a